If the difference between two numbers is 36and one number is 4 times the other number, then the numbers are
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Answer:
Let ,
The first number = x
Then , the second number = y
According to the question ,
x - y = 36
x = 36+y --(1)
x = 4y --(2)
Putting value of x from (1) in (2)
36+y = 4y
36 = 3y
y = 12
So x = 4y = 4*12 = 48
Therefore , the required numbers are 12 and 48
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