Question

If the difference between two supplementary angle is 40 degree then find the angles

Answer 1

$\huge{\mathfrak{\underline{Answer:}}}$

$\sf{\large{7 \: and \: 47}}$

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$\huge{\mathfrak{\underline{Solution:}}}$

Let the two suplementary angles be x and x + 40°.

$\sf \therefore x + x + 40\degree = 180 \degree \\ \\ \sf \to 2x = 180 \degree - 40 \degree \\ \\ \sf \to x = \frac{140}{2} \\ \\ \sf \to x = 7 \\ \\ \sf So \: the \: two \: angles \: are \: 7 \degree \: and \: 40 + 7 \: is \: 47 \degree.$

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Answer 2

$\huge{\mathbb{\underline{Answer:}}}$

Answer:

$\sf{\large{7 \: and \: 47}}$

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$\huge{\mathfrak{\underline{Solution:}}}$

Solution:

Let the two suplementary angles be x and x + 40°.

$\begin{lgathered}\sf \therefore x + x + 40\degree = 180 \degree \\ \\ \sf \to 2x = 180 \degree - 40 \degree \\ \\ \sf \to x = \frac{140}{2} \\ \\ \sf \to x = 7 \\ \\ \sf So \: the \: two \: angles \: are \: 7 \degree \: and \: 40 + 7 \: is \: 47 \degree.\end{lgathered}$