Question

If the difference of any two numbers is 3and difference of their squares is 39,find greatest number

Answer 1

y-x=3
y²-x²=39=(y+x)(y-x)=3(y+x)

So, y+x=13

So, y=8 and x=5

Answer 2

Let the 2 numbers be a and b.

So, a - b = 3 --(i)

And, a² - b² = 39
(a+b)(a - b) = 39
a + b = 39/3 = 13 ---(ii)

Equating both (i) and (ii),

2a = 16
a = 8

a - b = 3
b = 8 - 3 = 5

Hence required answer is a = 8

Hope This Helps You