Question

If the difference of two complementary angles is 10° then find measure of each angle.​

Answer 1

Answer:

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Step-by-step explanation:

Let first angle =x.

Let first angle =x.Then its complementary angle =90−x.

Let first angle =x.Then its complementary angle =90−x.Also, given that the difference of the complementary angles is 10 degree

Then,

Then,x−(90−x)=10

Then,x−(90−x)=10⟹x−90+x=10

Then,x−(90−x)=10⟹x−90+x=10⟹2x=10+90=100

Then,x−(90−x)=10⟹x−90+x=10⟹2x=10+90=100⟹x=50.

Then,x−(90−x)=10⟹x−90+x=10⟹2x=10+90=100⟹x=50.Second angle = 90−50=40.

Then,x−(90−x)=10⟹x−90+x=10⟹2x=10+90=100⟹x=50.Second angle = 90−50=40.Hence, the smaller angle =40.

Answer 2

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if one angle is x

other is 90-x =10 => x=80

thanks