if the difference of two digit number and number obtained by reversing the digit is 45 then write all possible 2 digit number
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Let the tens place digit be a and unit place digit be b
According to question,
(10a + b) - (10b +a) = 45
=> 10a + b - 10b - a = 45
=> 9a - 9b = 45
=> a - b = 5
=> a = b + 5
Possible 2 digits number satisfying this condition are :-
94, 83, 72, 61 and 50
According to question,
(10a + b) - (10b +a) = 45
=> 10a + b - 10b - a = 45
=> 9a - 9b = 45
=> a - b = 5
=> a = b + 5
Possible 2 digits number satisfying this condition are :-
94, 83, 72, 61 and 50
bhumika1916:
plz tell me how the number came
these numbers satisfy the condition, ie. tens place digit is 5 more than ones place digit
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This is the answer you want.
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