if the difference of two digit number and the number obtained by reversing the digits is 27 find the difference between the digits of the 2 digit number
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Let the tens place digit be a
And unit place be b
Number = 10a + b
Reversed number = 10b + a
(10a +b) - (10b +a) = 27
=> 10a +b - 10b - a = 27
=> 9a - 9b = 27
=> a - b = 3
Difference of digits = 3
And unit place be b
Number = 10a + b
Reversed number = 10b + a
(10a +b) - (10b +a) = 27
=> 10a +b - 10b - a = 27
=> 9a - 9b = 27
=> a - b = 3
Difference of digits = 3
ljkh:
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26
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