Question

If the dimensions of a square are increased by
50%, its area is increased by?​

Answer 1

Step-by-step explanation:

125% is the answer

please mark branliest

Answer 2

Answer:

• The area increases by 125%.

To find:

• If the dimensions of a square are increased by 50%, its area is increased by?

Solution:

Let the side of square be x units.

$\boxed{\sf{Area \ of \ square=Side^{2}}}$

Therefore, Area of square = x² sq units

According to the given condition

Side of square after increasing by 15%,

50% of x = x/2

Side after increasing by 50% = x + x/2 = 3x/2

Now,

Area of square = (3x/2)²

=> Area of square = 9x²/4 sq units

Now,

Difference in the areas

= Area of square after increasing side by 50% - Area of square

=> 9x²/4 - x²

=> (9x² - 4x²)/4

=> 5x²/4

Let the increase in area be k%

Now, k = (5x² × 100) / (4 × x²)

=> k = 5 × 25

=> k = 125%

Therefore, the area is increases by 125%.