Question

if the dipole moment of HI is 0.38D, and bond length is 1.6 angstrom, then% of covalent character in HI bond is???
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Answer 1

Answer:

We know that

μ=e×d

For complete separation of unit charge the dipole moment is calculated as

μ=1.602×10−19columb×1.275×10−10m=2.04Cm

Actual dipole moment of HCl = 1.03D = 0.34×10−29Cm(1Cm=2.9979×1029D)

% of ionic character of HCl = Actual dipole moment/calculated dipole moment x 100

=0.34×10−29Cm2.04×10−29Cm×100=17%

Explanation:

Answer 2

We know that

μ=e×d

For complete separation of unit charge the dipole moment is calculated as

μ=1.602×10−19columb×1.275×10−10m=2.04Cm

Actual dipole moment of HCl = 1.03D = 0.34×10−29Cm(1Cm=2.9979×1029D)

% of ionic character of HCl = Actual dipole moment/calculated dipole moment x 100

=0.34×10−29Cm2.04×10−29Cm×100=17%