Question

if the discriminant of the quadratic equation ax2+bx+c=0 is equal to zero then find the two equal roots​

Answer 1

We know that when discriminate is equals to 0 .Then,

Zeros of the quadratic equation

$= \frac{ - (co - efficient \: of \: x)}{2 \times \: co - effient \: of \: {x}^{2} } \\ \\ = > \frac{ - b}{2a}$

Answer 2

$\text{root}_1=\text{root}_1=-\dfrac{b}{2a}$

Step-by-step explanation:

Given : If the discriminant of the quadratic equation $ax^2+bx+c=0$ is equal to zero.

To find : The two equal roots​ ?

Solution :

We know that,

If the discriminant of the quadratic equation $ax^2+bx+c=0$ is equal to zero.

i.e. $D=b^2-4ac=0$

Then roots are given by,

$\text{root}_1=\text{root}_1=-\dfrac{\text{coefficient of x}}{2(\text{coefficient of}\ x^2)}$

Here, Coefficient of x = b

Coefficient of $x^2$ = a

Substitute the value,

$\text{root}_1=\text{root}_1=-\dfrac{b}{2a}$

#Learn more

If the quadratic equation px²-2√5px+15=0 has two equal roots, then find the value of p.

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