Math, asked by janaki1092004, 8 months ago

If the discriminat of 6x^2-bx+2=0 is 1, then the value of b is

Answers

Answered by aryan073
2

Step-by-step explanation:

6(1)²-b(1)+2=0

6-b+2=0

b=8 OK friend

Answered by brokenHeartSadGirl
0

Answer:

put the value of x = 1

6 * ( 1 )^2 - b*1 + 2 = 0

6 * 1 - b + 2 = 0

6 + 2 = b

8 = b

hence , the value of b is 8.

Similar questions
Math, 11 months ago