Question

If the displacement of a car is given by x=9t^2+5t+48 find the displacement, velocity and acceleration of the car after 3 sec.​

Answer 1

Answer:

after 3 sec

X=96 m

V=59 m/s

a=18 m/s²

Explanation:

At t=0

X=9×0×0+5×0+48

 =48 m

At t=3

X=9×3×3+5×3+48

 =81+15+48

  = 144 m

displacement = 144-48=96 m

velocity

after differentiating X we will get V

V=18t+5

At t=3

V= 18×3+5

 =54+5

 =59 m/s

Acceleration

after differentiating V we will get a

a= 18

a is not depended on t so after 3 sec it will remain same i.e. 18 m/s