If the distance between (3,a) and (-2,10) is 13 units find the value of a
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√ [ ( 3+2) ² + ( a -10)² ] = 13
=> [ ( 3+2) ² + ( a -10)² ] = 169
=> 25 + ( a -10)² = 169
=> ( a -10)² = 169 -25
=> ( a -10)² = 144
=> ( a -10) = √144
=> a -10 = 12
=> a = 22
Hope it helps you :)
=> [ ( 3+2) ² + ( a -10)² ] = 169
=> 25 + ( a -10)² = 169
=> ( a -10)² = 169 -25
=> ( a -10)² = 144
=> ( a -10) = √144
=> a -10 = 12
=> a = 22
Hope it helps you :)
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hope this helps you!!!! answer is (-2)
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