If the distance between A(2,3) and B(K,1) is 2√2,find the value of K
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aloha user!
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the distance between A(2,3) and B(K,1) is given to be 2√2.
we are gonna use distance formula.
x1= 2
x2 = k
y1 = 3
y2 = 1
distance= √(x2 - x1)² + (y2 - y1)
2√2 = √ ( k - 2 )² + (1 - 3 )²
2√2 = √ k² + 4 - 4k + 4
(2√2)² = k² - 4k +8
4 × 2 = k² - 4k + 8
8 = k² -4k + 8
0 = k² - 4k
0 = k ( k - 4 )
0 = k - 4
k = 4
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hope it helps :^)
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the distance between A(2,3) and B(K,1) is given to be 2√2.
we are gonna use distance formula.
x1= 2
x2 = k
y1 = 3
y2 = 1
distance= √(x2 - x1)² + (y2 - y1)
2√2 = √ ( k - 2 )² + (1 - 3 )²
2√2 = √ k² + 4 - 4k + 4
(2√2)² = k² - 4k +8
4 × 2 = k² - 4k + 8
8 = k² -4k + 8
0 = k² - 4k
0 = k ( k - 4 )
0 = k - 4
k = 4
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hope it helps :^)
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