A circus tent is cylindrical to a height of 8 m
surmounted by a conical part. If total height
of the tent is 13 m and the diameter of its base
is 24 m; calculate :
(i) total surface area of the tent,
(ii) area of canvas, required to make this tent
allowing 10% of the canvas used for folds
and stitching
Answers
Step-by-step explanation:
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Step-by-step explanation:
given,
height of cylinder=8
total height=13
height of cone=13-8=5
diameter of base= 24
radius of base= 12. (for both)
slant height of cone= √5²+12²
=√169
= 13
¡) TSA of tent= CSA of (cone+cylinder)
= πrl+πr²h
= πr(l+rh)
= 3.14×12(13+12×8)
= 3.14×12(13+96)
= 3.14×12× 109
= 4107.12
¡¡) area of canvas to cover the tent is 10% more
. than it so,
4107.12+4107.12×10/100
4107.12+410.712
4517.832
...........666............