If the distance between the point A(a, -) and B(5,3) be 5 units , find the value of 'a'
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2
Answer:
2
Step-by-step explanation:
distance=√(x2-x1)^2 +(y2-y1) ^2
5 =√(5-a)^2+(3+1)^2
25=(5-a)^2+4^2
25=(5-a)^2+16
25-16=(5-a)^2
9 =(5-a)^2
3 =5-a
a=5-3
a= 2
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