if the distance between the points A (4,K) and B(7,6) is 5 units then find the value of k
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AB = 5
AB² = 25
(7 - 4)² +( 6 - k)² = 25
9+36+k² -12k = 25
k² - 12k + 20 = 0
k² -2k -10k + 20 = 0
k(k-2) -10(k-2) = 0
either
(k-10) = 0. or k-2 = 0
then k = 10 or k= 2
AB² = 25
(7 - 4)² +( 6 - k)² = 25
9+36+k² -12k = 25
k² - 12k + 20 = 0
k² -2k -10k + 20 = 0
k(k-2) -10(k-2) = 0
either
(k-10) = 0. or k-2 = 0
then k = 10 or k= 2
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