Question

If the distance between the points (na, nb) and (a,

b.is 4 times the distance between the points (5a, 5b) and (a, b), then 'n' is equal to

Answer 1

this question is wrong you please move to other question otherwise you will be killed

Answer 2

Answer:

n can be 17 or - 15

Step-by-step explanation:

P=(na,nb)

Q = (a,b)

R =(5a,5b)

Now we are given that  the distance between the points (na, nb) and (a, b)is 4 times the distance between the points (5a, 5b) and (a, b),

So, $PQ= 4 \times QR$

Distance formula = $d =\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

Using Formula :

$\sqrt{(a-na)^2+(b-nb)^2}= 4 \times \sqrt{(5a-a)^2+(5b-b)^2}$

$(a-na)^2+(b-nb)^2= 16 \times((5a-a)^2+(5b-b)^2)$

$(a-na)^2+(b-nb)^2= 16 \times(16a^2+16b^2)$

$a^2(n-1)^2 +b^2(n-1)^2 =16 \times(16a^2+16b^2)$

$(n-1)^2 (a^2+b^2) =16^2(a^2+b^2)$

$(n-1)^2=16^2$

$n-1=\pm 16$

$n=+16+1, - 16+1$

$n=17,-15$

Hence n can be 17 or - 15