Question

If the distance between the points(x,2) and(3,-6) is 10 units what is the positive value of x

Answer 1

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Answer 2

here........,
distance between two points (x,2) &(3,-6)
is 10 units.

we may use the distance formula

(x,2)=>(x1,y1)
(3,-6)=>(x2,y2)

we know that,

$distance = \\\sqrt{( {x2 - x1)}^{2} + ({y2 - y1})^{2} }$


refer to image for the calculations and steps.

we get,


x=9
or
x=-3


but the positive value of x is 9