If the distance between two bodies is reduced to half and mass of each body is doubled, how does the gravitational force between two bodies change?pls help urgent(づ￣ ³￣)づ
Answers
Answer:
I keep getting asked this question and each time I pass because there are enough correct answers already. To stop the answer requests, I will add another correct answer:
The gravity equation is: F = G m1 m2 / r^2
Double the masses (m1 & m2) and halve the distance (r):
F’ = G 2 m1 2 m2 / (r/2)^2
F’ = 4 G m1 m2 / 1/4 r^2
F’ = 16 G m1 m2 / r^2
F’= 16 F
Explanation:
plz gave me brainilist mark.........!
Answer: First, look up Newton’s formula describing the gravitational force between two bodies. It looks like this:
F = G* m1*m2/(r^2)
Where
F = the gravitational force
G is the gravitational constant
m1 and m2 are the two masses
r is the distance between them
So the force is proportional to the two masses and inversely proportional to the square of the distance.
If you double each mass, you’ve increased the force by 2*2 or 4. If you halve the distance you’ve increased the force by 2*2 or 4.
So the combined result would increase the force by a factor of 16.