Question

if the distance between two electric charges is doubled, how much will the force exerting between them will change to?

Answer 1

F =kq1q2/r^2

F' = kq1q2/(2r)^2
=kq1q2/4r^2
=kq1q2/r^2 × 1/4
F' = F/4

therefore the force will change to F/4, that is decreases by 1/4th time.

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