if the distance between two points (8 x) and (x 8)=2root2 find the value of x
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Answer: mark it brainliest
Step-by-step explanation:
Formula of distance :-
√(x2-x1) + (y2-y1)
√(x-8)^2 + (8-x)^2
√x^2 + 64 - 16x + 64 + x^2 - 16x
√2x^2 + 128 - 32x = 2√2
Squaring both sides
2x^2 + 128 - 32x = 8
2x^2 - 32x + 120 = 0
Dividing both sides by 2
X^2 - 16x + 60 = 0
X^2 - 10x - 6x + 60 = 0
Taking common out
X(x-6) -10(x-6)
(x-6) (x-10)
Therefore x = 6
X= 10
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