Question

If the distance between two points (x, 7) and (1, 15) is 10, find the value of x.

Answer 1

√[(x-1)²+(15-7)²]=10

(x-1)²+64=100

(x-1)²=36

x-1=6           or     x-1=-6

x=7             or       x=-5

Answer 2

Answer:

The value of x is either 7 or -5.

Step-by-step explanation:

It is given that distance between two points (x, 7) and (1, 15) is 10.

Distance formula:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

$10=\sqrt{(1-x)^2+(15-7)^2}$

Squaring both sides.

$100=(1-x)^2+(8)^2$

$100=(1-x)^2+64$

$100-64=(1-x)^2$

$36=(1-x)^2$

Taking square root both sides.

$\pm \sqrt{36}=1-x$

$\pm 6=1-x$

$x=1\pm 6$

$x=1+6, x=1-6$

$x=7, x=-5$

Therefore the value of x is either 7 or -5.