If the distance of his relative’s home is denoted by x (in kms), and the total taxi fare by y (in Rs). Then, the correct relation between x and y ( Equation ) will be :
y =12x + 3.
y = 12x - 3
x = 12y + 3
x = 12y - 3
Answers
Complete question :- The taxi fare in a city is as follows : For the first kilometre, the fare is Rs.15 and for the subsequent distance it is Rs.12 per km. If the distance of his relative’s home is denoted by x (in kms), and the total taxi fare by y (in Rs). Then, the correct relation between x and y ( Equation ) will be :
y =12x + 3.
y = 12x - 3
x = 12y + 3
x = 12y - 3
Solution :-
given that,
→ Taxi fare for first kilometer = Rs.15
→ Taxi fare for subsequent distance = Rs.12/km .
→ Total distance covered = distance of his relative’s home = x km.
→ Total fare = Rs. y
As, we can see, the fare for first kilometer is Rs.15 and for for rest kilometer is Rs.12 .
So,
→ Fare for (x - 1) kilometer = 12(x - 1)
Therefore,
→ Total fare = fare for first km + fare for (x - 1) kms.
→ y = 12(x - 1) + 15
→ y = 12x - 12 + 15
→ y = 12x + 3. (Ans.)
Hence, the correct relation between x and y ( Equation ) will be : y = 12x + 3.
Answer:
given that,
→ Taxi fare for first kilometer = Rs.15
→ Taxi fare for subsequent distance = Rs.12/km .
→ Total distance covered = distance of his relative’s home = x km.
→ Total fare = Rs. y
As, we can see, the fare for first kilometer is Rs.15 and for for rest kilometer is Rs.12 .
So,
→ Fare for (x - 1) kilometer = 12(x - 1)
Therefore,
→ Total fare = fare for first km + fare for (x - 1) kms.
→ y = 12(x - 1) + 15
→ y = 12x - 12 + 15
→ y = 12x + 3. (Ans.)
Hence, the correct relation between x and y ( Equation ) will be : y = 12x + 3.