if the distance of the point P(x,y) from A(a,0) be (a+x) then prove that y^2=4ax
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distance between 2 points
√(x-a)^2+(y) ^2=a+x
squaring both sides
(x-a) ^2 -(a+x)^2 +y^2 =0
-4ax+y^2=0
y^2=4ax
proved
√(x-a)^2+(y) ^2=a+x
squaring both sides
(x-a) ^2 -(a+x)^2 +y^2 =0
-4ax+y^2=0
y^2=4ax
proved
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26
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