Question

If the distance travelled by a body in the nth second is given by (4+4n)m(4+4n)m , then find the initial velocity and acceleration of the body respectively​

Answer 1

Answer:

Answer

Correct option is

A

6 m s

−2

, 7 m s

−1

D

n

th

sec

=D

nsec

−D

(n−1)sec

4+6n=(un+

2

1

an

2

)−(u(n−1)+

2

1

a(n−1)

2

)

⟹4+6n=u−

2a+an

1

Comparing LHS and RHS

6n=an

⟹a=6m/s

2

4=u−

2

1

a

⟹4=u−3

⟹4=4+3=7m/s