if the distances of P(x,y) from A(5,1) and B(-1,5) are equal
then prove that 3x=2y.
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A(5,1)≡(x 1 ,y 1 )
B(−1,5)≡(x2 ,y 2 )
P≡(x,y)
PA=PB ....(given)
∴ By distance formula
√(x−x 1 )^ 2 +(y−y 1 ) ^2 we have,
⇒(x−5) ^2 +(y−1) ^2 =(x+1) ^2 +(y−5)2
⇒x^ 2 −10x+25+y ^2 −2y+1=x ^2 +2x+1+y^ 2 −10y+25
∴−2y+10y=2x+10x
∴−2y+10y=2x+10x∴8y=12y
2y=3x. [hence proved]
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