if the distinct real numbers a, b, c satisfy the equation (3x^3-2x^2+x+1)/(3x^3-2x^2-x-1)=(3x^3-2x^2+5x-13)/(3x^3-2x^2-5x+13) then find the value of 18 (a+b+c)
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Answer:
Let's solve your equation step-by-step.
3x3−2x2+x+1
3x3−2x2−x−1
=
3x3−2x2+5x−13
3x3−2x2−5x+13
Answer:
x=0 or x=
2
3
or x=
7
2
Step-by-step explanation:
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