Math, asked by prannavlight, 9 months ago

if the distinct real numbers a, b, c satisfy the equation (3x^3-2x^2+x+1)/(3x^3-2x^2-x-1)=(3x^3-2x^2+5x-13)/(3x^3-2x^2-5x+13) then find the value of 18 (a+b+c)

Answers

Answered by zitsatorosemary
4

Answer:

Let's solve your equation step-by-step.

3x3−2x2+x+1

3x3−2x2−x−1

=

3x3−2x2+5x−13

3x3−2x2−5x+13

Answer:

x=0 or x=

2

3

or x=

7

2

Step-by-step explanation:

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