Question

if the double of a natural is equal to the square of the numbers find, the number​

Answer 1

$\bigstar\huge\bf\underline{\underline{Answer:-}}$

Let the number be x

Then,

2x = x²

$\implies$ x² - 2x = 0

$\implies$ x(x - 2) = 0

$\implies$ x = 0 and x= 2

Therefore, the numbers are "0 and 2"

Answer 2

$\huge\cal{\colorbox{pink}{Ur\:Answer}}$

$\huge\red\bf{2\:and\:0}$

‎

The numbers are 2 and 0.

Proof:

$When\: we\: double\: 2 = 2\times2$

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎= 4

$The \:square \:of 2\: is = 2^2 = 4$

$When\: we\: double\: 0 = 0\times0$

‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎ ‎= 0

$The\: square \:of \:0 \:is = 0^2 = 0$

The values of double and square is itself for only 2 and 0.

So, the numbers are 0 and 2......

$\cal\purple{hope\:it\:helps\:uh❗}$