Question

if the earth strings to 50 percentage of its real radius its mass remaining the same the weight of your body on the earth will​

Answer 1

Answer:

As the mass of the earth remains same, so initially the gravitational acceleration,

As the mass of the earth remains same, so initially the gravitational acceleration,g=R2GM and after shrinks g′=(R/2)2GM=4g

As the mass of the earth remains same, so initially the gravitational acceleration,g=R2GM and after shrinks g′=(R/2)2GM=4g% change in weight =mgmg′−mg×100=gg′−g×=g4g−g×100=300 %

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