sin teta / 1 -cos teta =1+cos teta /sin teta
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Answer:
sinθ/1-cosθ=1+cosθ/sinθ
LHS:
=sinθ/1-cosθ
conjugate 1-cosθ
= sinθ/1-cosθ *1+cosθ/1+cosθ
= sinθ(1+cosθ)/(1-cosθ)(1+cosθ)
=sinθ+sinθcosθ/1-cos²θ
=sinθ(1+cosθ)/sin²θ
=1+cosθ/sinθ
LHS=RHS
hence proved
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