Question

sin teta / 1 -cos teta =1+cos teta /sin teta​

Answer 1

Answer:

sinθ/1-cosθ=1+cosθ/sinθ

LHS:

     =sinθ/1-cosθ

     conjugate 1-cosθ

     = sinθ/1-cosθ *1+cosθ/1+cosθ

     = sinθ(1+cosθ)/(1-cosθ)(1+cosθ)

     =sinθ+sinθcosθ/1-cos²θ

     =sinθ(1+cosθ)/sin²θ

     =1+cosθ/sinθ

LHS=RHS

hence proved