Question

if the edge length of an fcc crystal lattice is 400 pm. calculate the radius of atom​

Answer 1

Answer:

For an octahedral void a = 2 (r + R) In fcc lattice the largest void present is octahedral void. If the radius of void sphere is R and of lattice atom is r. Then,r= 2×400/5=141.12pm (a=400pm)

2R=a−2×r=400–2×141.12

∴ Diameter of atom = 117.16 pm

Radius = Diameter/2

Therefore, Radius of atom is 58.58