Question

x + π

solve
x^3 + 3x^2 + 3x + 1​

Answer 1

$x + \pi \\ x + \pi = 0 \\ x = - \pi$

${x}^{3} + 3 {x}^{2} + 3x + 1$

$= ( { - \pi})^{2} + 3( { - \pi})^{2} + 3( - \pi) + 1$

$= { -\pi}^{3} + 3 { - \pi}^{2} - 3\pi + 1$

hope it helps u....!!

Answer 2

$x + \pi \\ x + \pi = 0 \\ x = - \pi$

${x}^{3} + 3 {x}^{2} + 3x + 1$

$= ( { - \pi})^{2} + 3( { - \pi})^{2} + 3( - \pi) + 1$

$= { -\pi}^{3} + 3 { - \pi}^{2} - 3\pi + 1$

hope it helps u....!!