if the edge of a cube is increased by 50% ,then find the % of increase in surface area and its increase in volume
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a'=a+0.5a=1.5a
Area'=6a'^2=6 (1.5a)^2=2.25 (6a^2)=2.25Area
Percent Increase=(2.25area-area)/area× 100
=1.25×100=125%
Vol.'=a^3=(1.5a)^3=3.375a^3=3.375a^3=3.375× Vol.
Percent increase =(3.375-1)×100=237.5%
abhi60:
i think ur answer is wrong
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Percent increase in area of the cube is 125 %
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