If the edges of a room are in the ratio 3:2:1 and its total surface area is 198 sq.m. What is the length of the room?
Answers
Step-by-step explanation:
We know that a room is in the shape of a cuboid
Therefore,let length(l) = 3x
breadth(b) = 2x
height(h) = 1x = x
(GIVEN) Total surface area(T.S.A.) = 198 sq.m
& we know T.S.A. = 2(lb + bh + hl)
=> 2(lb + bh + hl) = 198sq.m
(NOW FILL IN THE VALUES OF l,b & h FROM ABOVE IN THE ABOVE FORMULA)
2(3x × 2x + 2x × x + x ×3x) = 198
2(6x^2 + 2x^2 + 3x^2) = 198
11x^2 = 198÷2
11x^2 = 99
x^2 = 9
therefore,x = 3m
NOW,We know that ( l = 3x )
Put value of x in ( l = 3x )
therefore, length ( l ) =( 3 × 3)m
= 9m Ans.
Answer:
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