Question

please answer
my paper is going on.​

Answer 1

Answer:

In BCA, DE AC

[Basic Proportionality theorem] ……….(i)

And in BEA, DF AE

[Basic Proportionality theorem] ……….(ii)

From eq. (i) and (ii), we have

Answer 2

Answer:

in BPA ,we,have dc|| Ap (given) therefore by basic proportionally theorem ,we have BC ÷cp =BD ÷da in BCA ,we have de ||ac

therefore by basic proportionally theorem ,we have be÷ec =bd÷da

from (1) and (2) we, get

bc÷cp =be ÷ec or be÷ec=BC ÷cp

hence proved

I hope it ☝️helps ur paper

please mark has a brainlest