Question

if the electric field near the earth surface be 300 volt/m directed downwards. What is the surface density of charge on earth surface ?​

Answer 1

Explanation:

eo = 8.85 * 10 -12

E = 300 V/m

ψ = E * Area = q / eo

σ = E*eo = q/Area

= E * eo

= 2.655*10

Answer 2

Answer:

The surface density of charge on earth surface is $26.56\times 10^{ -10 }Cm^{-2}$.

Explanation:

Given electric field near the earth surface directed downwards is

$E= 300 V/m=300 N/C$

Surface charge density is defined as the amount of charge, q distributed per unit surface area, A.

$\sigma=\dfrac{q}{A}$

Electric flux is defined as the number of electric field lines passing through an unit area.

$\phi=EA$                                                 ...(1)

According to Gauss's law, the electric flux out of a closed surface is equal to the charge enclosed divided by the electric permittivity.

$\phi=\dfrac{q}{\varepsilon_0}$                                                  ...(2)

where $\varepsilon_0=8.85 \times 10^{ -12 }C^2N^{-1}m^{-2}$ is the electric permittivity of free space.

Combining both the equations,

$EA=\dfrac{q}{\varepsilon_0}\implies E{\varepsilon_0}=\dfrac{q}{A}=\sigma$

Substituting the given values, the surface density of charge is

$\sigma= E{\varepsilon_0}$

  $=300\times8.854 \times 10^{ -12 }=26.56\times 10^{ -10 }Cm^{-2}$

Therefore, the surface density of charge on earth surface is

$26.56\times 10^{ -10 }Cm^{-2}$.

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