If the empirical formula of two compounds is ch and their vapour density is 13 and 39 respectively find the
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Do we have to find the molecular formula. If it is so then MW = n(EM). EM = CH = 12+1 = 13 MW1 = 2*13= 26. MW2 = 2* 39 = 78. THEREFORE n1 = 26/13 = 2. n2 = 78/13 = 6. THUS. MF¹ = C2H2. MF²= C6H6. I HOPE THIS ANSWER WILL HELP YOU
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