If the numerator of a fraction is increased by 20% and its denominator is decresed by 10% the fraction becomes 3/2 what is the value of the original fraction
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GIVEN
1. Numerator of a fraction is increased by 20%
2. Denominator is decresed by 10%
3. The new fraction becomes 3/2.
CASE 1.
Let the numerator be X
Then
X + (20X/100) = 3
X + (X / 5) = 3
LCM = 5
(5 + 1)X / 5 = 3
6X = 15
X = 15 / 6
X = 5 / 2
CASE 2.
Let the numerator be Y
Then
Y + (10Y/100) = 2
Y + (Y / 10) = 2
LCM = 10
(10 + 1)Y / 10 = 2
11Y = 20
Y = 20 / 11
FRACTION
X / Y = (5 / 2) / (20 / 11)
X / Y = 55 / 40
X / Y = 11 / 8
This is our original fraction.
1. Numerator of a fraction is increased by 20%
2. Denominator is decresed by 10%
3. The new fraction becomes 3/2.
CASE 1.
Let the numerator be X
Then
X + (20X/100) = 3
X + (X / 5) = 3
LCM = 5
(5 + 1)X / 5 = 3
6X = 15
X = 15 / 6
X = 5 / 2
CASE 2.
Let the numerator be Y
Then
Y + (10Y/100) = 2
Y + (Y / 10) = 2
LCM = 10
(10 + 1)Y / 10 = 2
11Y = 20
Y = 20 / 11
FRACTION
X / Y = (5 / 2) / (20 / 11)
X / Y = 55 / 40
X / Y = 11 / 8
This is our original fraction.
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