If the endpoints of the diameter of a circle are (3,10) and (−1,6), what are the coordinates of its center?
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Answer:
coordinate of the midpoint is (1,8)
Step-by-step explanation:
A(3,10) B(-1,6)
midpoint of AB,
((x1+x2)/2, (y1+y2)/2) = [(3-1)/2 , (10+6)/2]
= (1,8)
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