If the energy of a ball falling from a height of 10 m is reduced by 40 % how high will it rebound
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on reaching the ground the energy of the object = the energy at the top [law of conservation of mass]
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Hey dear,
● Answer -
Ball will rebound by 6 m
● Explanation -
Let h be the height from which ball is dropped & h' be height to which ball rebounds.
As energy of the ball is reduced by 40%.
∆E = 40% E
E - E' = 40% E
mgh - mgh' = 40/100 × mgh
h' = (1 - 2/5) h
h' = 6/10 × 10
h' = 6 m
Therefore, ball will rebound to the height of 6 m.
Thanks for asking dear.
● Answer -
Ball will rebound by 6 m
● Explanation -
Let h be the height from which ball is dropped & h' be height to which ball rebounds.
As energy of the ball is reduced by 40%.
∆E = 40% E
E - E' = 40% E
mgh - mgh' = 40/100 × mgh
h' = (1 - 2/5) h
h' = 6/10 × 10
h' = 6 m
Therefore, ball will rebound to the height of 6 m.
Thanks for asking dear.
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