Question

If the energy of a photon corresponding to wavelength of 6000 A° is 3.32 X10-19 J, the photon energy for wavelength of 4000 A° will be

Answer 1

Given that,

Energy of a photon corresponding to wavelength of 6000 A° is $3.32\times 10^{-19}\ J$

To find,

The energy of photon for wavelength of 4000 A°.

Solution,

The formula that is used to find the energy of a photon is given as follows :

$E=\dfrac{hc}{\lambda}$

⇒$E\propto \dfrac{1}{\lambda}\\\\\dfrac{E_1}{E_2}=\dfrac{\lambda_2}{\lambda_1}\\\\\dfrac{3.32\times 10^{-19}}{E_2}=\dfrac{4000}{6000}\\\\E_2=\dfrac{3.32\times 10^{-19}\times 6000}{4000}\\\\E_2=4.98\times 10^{-19}\ J$

So, the energy of the photon for wavelength of 4000 A is $4.98\times 10^{-19}\ J$.