Chemistry, asked by chicagosingless755, 1 year ago

If the energy of an electron in the second Bohr orbit of H-atom is -E, what is the energy of the electron in the Bohr’s first orbit?
a) 2E
b) -4E
c) -2E
d) 4E

Answers

Answered by abhi178
9
we know, energy of electron in nth orbit is given by
\bold{E_n=-13.6\frac{\mathbb{Z}^2}{n^2}}}
Here Z is atomic number and n is orbit in which electron revolves around the nucleus .

so, you can see that energy of electron in nth orbit is inversely proportional to n²
For same hydrogen like atom.

Here, energy of electron in 2nd orbit ,E₂ = - 13.6 × 1²/2² = -E ---(1)[ when z = 1 ]
Also energy of electron in 1st orbit , E₁ = - 13.6 × 1²/1²
From equation (1),
E₁ = 4 × (-E) = -4E

Hence, option ( b) is correct.
Answered by manishgupta4138
3

Answer:

Explanation:i hope its clear!!

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