Question

If the energy of the electron in H atom is given by expression -1312/n^2KJ mol^-1. Then the energy required to
excite the electron from ground state to second orbit is​

Answer 1

According to the equation,

Energy in first orbit = -1312/1² = 1312

And energy in second orbit = -1312/2² = -328

Thus energy required = -328 - (-1312) = 984

plz mark it as brainliest

b..bye

#ANSWERWITHQUALITY

#BAL

Answer 2

$\mathfrak{ \huge{ \red{ \underline{ \underline{Answer}}}}} \\ \\ \implies \: \sf \: energy \: in \: first \: orbit = \frac{ - 1312}{ {1}^{2} } \: kJ \\ \\ \implies \: \sf \: energy \: in \: second \: orbit = \frac{ - 1312}{ {2}^{2} } \: kJ \\ \\ \implies \: \sf \: energy \: requires \: to \: excite \: from \: first \: orbit \: to \: second \: orbit \\ \\ \implies \: \sf \: E = - 1312 \: ( \frac{1}{4} - \frac{1}{1} ) = 984 \: kJ \\ \\ \implies \: \boxed{ \boxed{ \blue{ \bold{ \sf{energy \: requires = 984 \: kJ}}}}}$