Question

If the energy released in the fission of one nucleus is 3.2 * 10^-11J, then find the number of nuclei required per second in a power plant of 16kW

Answer 1

Answer:

0.5×1014  

0.5×1012

5×1012

5×1014

Answer :

D

Solution :

(d) Energy released in the fission of one nucleus

=200MeV

=200×106×1.6×10−19J=3.2×10−11J

P=16KW=16×103Wa

Now, number of nuclei required per second

n=PE=16×1033.2×10−11=5×1014.