Question

if the equation (3x)^2+(27*3^1/k-15)x+4=0 has equal roots then k is??
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Answer 1

Step-by-step explanation:

Explanation:

$( \frac{1}{x} + 2) + ( \frac{2}{x} - 1) = \frac{6}{x} \\ \\ \frac{1}{x} + 2 + \frac{2}{x} - 1 = \frac{6}{x} \\ \\ \frac{3}{x} + 1 = \frac{6}{x} \\ \\ \frac{6}{x} - \frac{3}{x} = 1 \\ \\ \frac{6 - 3}{x} = 1 \\ \\ \frac{3}{x} = 1 \\ \\ x = 3$