if the equation (a square + b square) x square - 2 A(A + c )X + b square + c square equal to zero has equal roots then
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Step-by-step explanation:
let roots are alfa and beta
given alfa = beta = alfa+beta=
2alfa = -2A(A+c) / (a²+b²)
=> alfa² = A²(A+c)²/ (a²+b²)²............(1)
again
alfa× beta= alfa× alfa=
alfa² = (a²+b²) / 2A(A+c).................(2)
from (1) and (2)
2A³(A+c)³ = (a²+b²)³
=> ³√2A(A+c) = a²+b²
Hope this helps you
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