Math, asked by devarajn1976, 1 year ago

if the equation ax square + 2 b x + 3 C is equal to zero and 3 X square + 8 x + 15 is equal to zero have a common root wear a b c are the lengths of the sides of a triangle ABC then sin square A + sin square b + sin square C is equal to

Answers

Answered by amritaraj
2

Answer:

Step-by-step explanation:

Step-by-step explanation:

3(x^2)-ax+6 = a(x^2)+2x+2

=> (x^2)(3-a)-x(a+2)+4=0

If a quadratic equation(ax^2+bx+c=0) has equal roots, then discriminant should be zero i.e. b^2-4ac=0

Here a=3-1 ; b=-(a+2) ; c=4

(-(a+2))^2 - 4(3-a)*4 = 0

a^2 + 4 + 4a - 16(3-a)=0

a^2 + 4 + 4a - 48 + 16a = 0

a^2 + 20a - 44 = 0

(a+22)(a-2)=0

a=2

When a=2, equation becomes (x^2)(3-2)-x(2+2)+4=0

x^2-4x+4 =0

x=2

Answered by rishu6845
2

Answer:

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