Question

If the equation ax2 + 2x - 2 = 0 has real and distinct roots, then the value of a is​

Answer 1

Step-by-step explanation:

we can easily find the value of a by using the formula discriminant formula

a= 1

b= 2

c=-2

Using discriminant formula

$x = - b \frac{ + } \: \sqrt{ {b}^{2} - 4ac } \div 2 \\ x = - 2 \frac{ + } \: \sqrt{ { - 2}^{2} + 8} \div 2 \\ x = - 2 \frac{ + } \: \sqrt{ {4} + 8 } \div 2 \} \\ x = - 2 \frac{ + } \: \sqrt{12} \div 2 \\ x = - 2 + \sqrt{12} \div 2 \\ x = - 2 - \sqrt{12} \div 2$

now put the value of x in eq I

u will get the value

Answer 2

Step-by-step explanation:

D>0

b^2-4ac>0

put value of b and c

so,4+8a>0(subtract 4)

8a>-4(divide by 8

a>-1/2