Question

If the equation (k+1)x2-2(k-1)x+1=0 has the equal roots then find the value of k

Answer 1

heya!!

refer to given attachment please

Answer 2

Answer:

The values of k are 0 and 3

Step-by-step explanation:

We know that for equal roots of a  quadratic equation, the discriminant should be zero.  

Therefore, we have

$D=0\\\\b^2-4ac=0\\\\(-2(k-1))^2-4(k+1)(1)=0\\\\4(k-1)^2-4(k+1)=0\\\\\text{Take 4 common}\\\\(k-1)^2-k-1=0\\\\\text{On simplifying, we get}\\\\k^2+1-2k-k-1=0\\\\k^2-3k=0\\\\\text{Take k common}\\\\k(k-3)=0\\\\k=0,3$

Therefore, the values of k are 0 and 3