Question

If the equation kx2+4x+1=0 has real and distinct roots then find the value of k

Answer 1

I hope it will help you.

Answer 2

Answer:

For all real value of k<4, the equation have real and distinct roots.

Explanation:

Given quadratic equation:

kx²+4x+1=0

Compare above equation with

ax²+bx+c=0, we get

a = k , b = 4 , c = 1

Discreminant (D)>0

/* Given roots are real and distinct */

b²-4ac > 0

=> 4²-4×k×1>0

=> 16-4k >0

=> -4k>-16

Divide both sides by (-4), we get

=> k < 4

Therefore,

For all real value of k<4, the equation have real and distinct roots.

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